The root of the equation 2(1+i) x²-4(2-i) x-5-3 i=0 which has greater modulus is

Step-by-step solution

aligned Roots &= 4(2-i) 16(2-i)²+8(1+i)(5+3 i) 4(1+i) &= 4-i 1+i or -i 1+i = 3-5 i 2 or -1-i 2 aligned