If complex number z₁, z₂ and 0 are vertices of equilateral triangle, then z₁²+z₂²-z₁ z₂ is equal to

Step-by-step solution

z₁, z₂, 0 are vertices of an equilateral triangle, so we have z₁²+z₂²+0²=z₁ z₂+z₂ 0+0 z₁ z₁²+z₂²=z₁ z₂ z₁²+z₂²-z₁ z₂=0