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BITSAT 2011
Exam
BITSAT
Year
2011
Subject
Mathematics
Chapter
Complex Number

BITSAT 2011 · Mathematics · Complex Number

If (a > 0, a ∈ ℝ, z=a+2 i) and z|z|-a z+1=0 then

If (a > 0, a \in R,\mathbb{R},z=a+2 i) and z∣z∣−az+1=0z|z|-a z+1=0 then

Options

  1. Azz is always a positive real number
  2. Bzz is always a negative real number
  3. Czz is purely imaginary number
  4. Dsuch a complex z does not exist

Correct answer

D. such a complex z does not exist

Step-by-step solution

Putting z=a+2iz=a+2 i in the given equation and comparing imaginary parts, we get (\mathrm{a}^2+4=\mathrm{a}^2), which is not possible.
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