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BITSAT 2010
Exam
BITSAT
Year
2010
Subject
Mathematics
Chapter
Complex Number

BITSAT 2010 · Mathematics · Complex Number

The roots of the equation (x²-2 2 x+1=0) are

The roots of the equation (x²-2 2\sqrt{2}x+1=0) are

Options

  1. AReal and different
  2. BImaginary and different
  3. CReal and equal
  4. DRational and different

Correct answer

A. Real and different

Step-by-step solution

The discriminant of the equation ((-2 \sqrt{2})^2-4(1)(1)=8-4=4 \gt 0) and aa perfect square, so roots are real and different but we can't say that roots are rational because coefficients are not rational therefore. (22±(22)2−42=22±22=2±\frac{\sqrt{2 \sqrt{2} \pm \sqrt{(2 \sqrt{2})^2-4}}}{2}=\frac{2 \sqrt{2} \pm 2}{2}=\sqrt{2} \pm1) this is irrational (\therefore) the roots are real and different.
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