Two blocks are connected over a massless pulley as shown in fig. The mass of block A is 10 ~kg and the coefficient of kinetic friction is 0.2 . Block A slides down the incline at constant speed. The mass of block B in kg is:

Step-by-step solution

Considering the equilibrium of A, we get array l 10 a =10 ~g 30^ - T - N where N =10 ~g 30^ array 10 a = 10 2 ~g - T - 10 ~g 30^ but a =0, ~T = m _ B g 0=5 ~g - m _ B g - 0.2 3 2 10 g m _ B =3.268 3.3 ~kg