JEE Advanced 2016Paper 1
- Exam
- JEE Advanced
- Year
- 2016
- Paper
- Paper 1
- Subject
- Chemistry
- Chapter
- Chemical Kinetics
JEE Advanced 2016 · Paper 1 · Chemistry · Chemical Kinetics
A plot of the number of neutrons ( N ) against the number of...
A plot of the number of neutrons against the number of protons of the stable nuclei exhibits upwards deviation from linearity for atomic number, . For an unstable nucleus having ratio less than , the possible mode(s) of decay is (are):
Options
- A decay ( emission)
- BOrbital of K-electron capture
- CNeutron emission
- D decay (positron emission)
Correct answer
B. Orbital of K-electron capture
Step-by-step solution
As ratio is less than , for possible decay mode, ratio should increase. The possible modes are -decay, K-capture and -decay. Hence, the correct options are \left(2\right) and \left(4\right) (In neutron decay, \dfrac{N}{P} ratio will decrease further).
\dfrac{N}{P} s{}_{0}{e}^{- 1} + p 11 ⟶ n 10p 11 ⟶ n 10 + \beta 01{\beta}^{+}-decay]
\dfrac{N}{P} s{}_{0}{e}^{- 1} + p 11 ⟶ n 10p 11 ⟶ n 10 + \beta 01{\beta}^{+}-decay]