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JEE Advanced 2016Paper 1
Exam
JEE Advanced
Year
2016
Paper
Paper 1
Subject
Chemistry
Chapter
Chemical Kinetics

JEE Advanced 2016 · Paper 1 · Chemistry · Chemical Kinetics

According to the Arrhenius equation,

According to the Arrhenius equation,

Options

  1. AA high activation energy usually implies a fast reaction
  2. BRate constant increase with increase in temperature. This is due to a greater number of collisions whose energy exceeds the activation energy
  3. CHigher the magnitude of activation energy, stronger is the temperature dependence of the rate constant
  4. DThe pre-exponential factor is a measure of the rate at which collisions occur, irrespective of their energy.

Correct answer

B. Rate constant increase with increase in temperature. This is due to a greater number of collisions whose energy exceeds the activation energy

Step-by-step solution

A] k=Ae−Ea/RTk = A{e}^{- {E}_{a} / RT}
High Ea{E}_{a} means less k, hence slower rate.
B] e−Ea/RT{e}^{- {E}_{a} / RT} = fraction of molecules having kinetic energy greater than activation energy which increase as temperature increases.
C] ln k2k1=EaR\dfrac{{k}_{2}}{{k}_{1}} = \dfrac{{E}_{a}}{R}\left[\dfrac{1}{{T}_{1}} - \dfrac{1}{{T}_{2}}\right]i.e.,lni.e., ln\dfrac{{K}_{2}}{{k}_{1}} ∝ {E}_{a}<br/>D]Rateofreaction<br />D] Rate of reaction∝Totalnumberofcollisions×Fractionofcollisionswhichcanformproduct<br/>RateofreactionTotal number of collisions × Fraction of collisions which can form product<br />Rate of reaction∝ {Z}_{AB} \times \left(P \times {e}^{- {E}_{a} / RT}\right)<br/><br />∝ A{e}^{- {E}_{a} / RT}
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