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JEE Advanced 2015Paper 2
Exam
JEE Advanced
Year
2015
Paper
Paper 2
Subject
Chemistry
Chapter
Chemical Kinetics

JEE Advanced 2015 · Paper 2 · Chemistry · Chemical Kinetics

A closed vessel with rigid walls contains 1 mol of U 92238 and 1...

A closed vessel with rigid walls contains 1 mol of U92238U 92238 and 1 mol of air at 298 K. Considering complete decay of U92238U 92238 to Pb82206Pb 82206 , the ratio of the final pressure to the initial pressure of the system at 298 K isA closed vessel with rigid walls contains 1 mol of U 92238 and 1 mol of air at 298 K. Considering complete decay of U

Correct answer

9

Step-by-step solution

Initial moles of gases = 1

A closed vessel with rigid walls contains 1 mol of U 92238 and 1 mol of air at 298 K. Considering complete decay of U
Total gaseous moles after decomposition =8+1=9moles= 8 + 1 = 9moles
Ratio of pressures, PfPi=nfni=9\dfrac{{P}_{f}}{{P}_{i}} = \dfrac{{n}_{f}}{{n}_{i}} = 9

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