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JEE Main 20169 AprilOnline
Exam
JEE Main
Year
2016
Date
9 April
Mode
Online
Subject
Chemistry
Chapter
Chemical Kinetics

JEE Main 2016 · 9 April · Online · Chemistry · Chemical Kinetics

The reaction of ozone with oxygen atoms in the presence of chlorine...

The reaction of ozone with oxygen atoms in the presence of chlorine atoms can occur by a two step process shown below:

O3(g)+Cl•→O2(g)+ClO•(g){O}_{3}\left(g\right) + {Cl}^{•} \to {O}_{2}\left(g\right) + {ClO}^{•}\left(g\right) ...(i)

ki=5.2×109Lmol−1s−1{k}_{i} = 5.2 \times {10}^{9}Lmo{l}^{- 1}{s}^{- 1}

ClO•(g)+O•(g)→O2(g)+Cl•(g){ClO}^{•}\left(g\right) + {O}^{•}\left(g\right) \to {O}_{2}\left(g\right) + {Cl}^{•}\left(g\right) ...(ii)

kii=2.6×1010Lmol−1s−1{k}_{ii} = 2.6 \times {10}^{10}Lmo{l}^{- 1}{s}^{- 1}

The closest rate constant for the overall reaction

O3(g)+O•(g)→2O2(g){O}_{3}\left(g\right) + {O}^{•}\left(g\right) \to 2{O}_{2}\left(g\right) is:

Options

  1. A1.4×1020Lmol−1s−11.4 \times {10}^{20}Lmo{l}^{- 1}{s}^{- 1}
  2. B3.1×1010Lmol−1s−13.1 \times {10}^{10}Lmo{l}^{- 1}{s}^{- 1}
  3. C5.2×109Lmol−1s−15.2 \times {10}^{9}Lmo{l}^{- 1}{s}^{- 1}
  4. D2.6×1010Lmol−1s−12.6 \times {10}^{10}Lmo{l}^{- 1}{s}^{- 1}

Correct answer

A. 1.4×1020Lmol−1s−11.4 \times {10}^{20}Lmo{l}^{- 1}{s}^{- 1}

Step-by-step solution

O3(g)+Cl(g)•→O2(g)+ClO(s)•KiClO(g)•+O(g)•→O2(g)+Cl(g)•Kii\begin{array}{ll}{O}_{3\left(g\right)} + {Cl}_{\left(g\right)}^{•}\mathop{\to}_{}^{}{O}_{2\left(g\right)} + {ClO}_{\left(s\right)}^{•}{K}_{i} \\ {ClO}_{\left(g\right)}^{•} + {O}_{\left(g\right)}^{•}\mathop{\to}_{}^{}{O}_{2\left(g\right)} + {Cl}_{\left(g\right)}^{•}{K}_{ii}\end{array}

_________________________________

O3(g)+O(g)•→202(g)KRate=Ki×Kii{O}_{3\left(g\right)} + {O}_{\left(g\right)}^{•}\mathop{\to}_{}^{}{20}_{2\left(g\right)}{K}_{Rate} = {K}_{i} \times {K}_{ii}

Overall Rate constant =Ki×Kii= {K}_{i} \times {K}_{ii}

=5.2×109×2.6×1010= 5 . 2 \times {10}^{9} \times 2 . 6 \times {10}^{10}

≈1.4×1020mol−1Ls−1\approx 1 . 4 \times {10}^{20}{mol}^{- 1}L{s}^{- 1}
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