The calculated spin only magnetic moments of [Cr ( NH _ 3 ) _ 6 ] ^...

Spin only magnetic moment can be calculated using the formula $\mu = \sqrt{n\left(n + 2\right)}$B . M$<p>$n =$number of unpaired electron at central atom.</p><p>${\left[Cr{\left({NH}_{3}\right)}_{6}\right]}^{3 +}$:${Cr}^{3 +}$is the central metal ion.</p><p>${Cr}^{3 +}$:$3{d}^{3}$configuration</p><p> It has three unpaired electrons.</p><p>$\mu = \sqrt{3\left(3 + 2\right)}BM = 3 .87 BM$</p><p>${\left[{CuF}_{6}\right]}^{3 -}$:${Cu}^{3 +}$is the central metal ion.</p><p>${Cu}^{3 +}$:$3{d}^{8}$configuration</p><p>Fluorine is the weak field ligand. Its electronic configuration is${t}_{2g}^{6}{e}_{g}^{2}$. Hence, it has two unpaired electrons.</p><p>$\mu = \sqrt{2\left(2 + 2\right)}BM = 2 .84 BM