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The volume (in mL ) of 0.1 M AgNO ₃ required for complete precipitation of chloride ions present in 30 ~mL of 0.01 M solution of [ Cr ( H ₂ O _ )₅ Cl ] Cl ₂ . , as silver chloride is close to

Correct answer

6

Step-by-step solution

mmol of complex =30 0.01=0.3 Also, 1 mole of complex [ Cr ( H ₂ O )₅ Cl ] Cl ₂ gives only two moles of chloride ion when dissolved in solution [ Cr ( H ₂ O )₅ Cl ] Cl ₂ [ Cr ( H ₂ O )₅ Cl ²⁺+2 Cl ⁻ . mmol of Cl ⁻ ion produced from its 0.3 mmol =0.6 Hence, 0.6 mmol of Ag ⁺ would be required for precipitation. aligned & 0.60 mmol of Ag ⁺=0.1 M V ( in mL ) & V=6 ~mL . aligned

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