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JEE Advanced 2008Paper 2
Exam
JEE Advanced
Year
2008
Paper
Paper 2
Subject
Chemistry
Chapter
Coordination Compounds

JEE Advanced 2008 · Paper 2 · Chemistry · Coordination Compounds

Statement 1[Fe(H_2 O)_5 NO] SO_4 is paramagnetic. Statement 2 The...

Statement 1[Fe(H2O)5NO]SO4\mathbf{1}\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_5 \mathrm{NO}\right] \mathrm{SO}_4 is paramagnetic. Statement 2 The Fein[Fe(H2O)5NO]SO4\mathrm{Fe} in \left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_5 \mathrm{NO}\right] \mathrm{SO}_4 has three unpaired electrons.

Options

  1. AStatement 1 is true, Statement 2 is true, Statement 2 is a correct explanation for Statement 1.
  2. BStatement 1 is true, Statement 2 is true, Statement 2 is not a correct explanation for Statement 1.
  3. CStatement 1 is true, Statement 2 is false.
  4. DStatement 1 is false, Statement 2 is true

Correct answer

A. Statement 1 is true, Statement 2 is true, Statement 2 is a correct explanation for Statement 1.

Step-by-step solution

The oxidation number of Fe\mathrm{Fe} in the complex, \left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_5 \mathrm{NO}\right] \mathrm{SO}_4isis+1[[\mathrm{NO}hashas+1charge]charge ]\mathrm{Fe}^{+}=[\mathrm{Ar}]3d64s13 d⁶ 4 s¹\mathrm{NO}^{+}causespairingof4selectroninside.Thus,theconfigurationiscauses pairing of 4 s electron inside . Thus, the configuration is3 d^7 and number of unpaired electrons =3=3
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