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JEE Advanced2008ChemistryCoordination CompoundsActual

Statement 1 [ Fe ( H ₂ O )₅ NO ] SO ₄ is paramagnetic. Statement 2 The Fe in [ Fe ( H ₂ O )₅ NO ] SO ₄ has three unpaired electrons.

Options

  1. AStatement 1 is true, Statement 2 is true, Statement 2 is a correct explanation for Statement 1.
  2. BStatement 1 is true, Statement 2 is true, Statement 2 is not a correct explanation for Statement 1.
  3. CStatement 1 is true, Statement 2 is false.
  4. DStatement 1 is false, Statement 2 is true

Correct answer

A. Statement 1 is true, Statement 2 is true, Statement 2 is a correct explanation for Statement 1.

Step-by-step solution

The oxidation number of Fe in the complex, [ Fe ( H ₂ O )₅ NO ] SO ₄ is +1 [ NO has +1 charge ] Fe ⁺=[ Ar ] 3 d^6 4 s^1 NO ⁺ causes pairing of 4 s electron inside . Thus, the configuration is 3 d^7 and number of unpaired electrons =3

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