Paragraph: The coordination number of Ni ²⁺ is 4 . NiCl ₂+ KCN (excess) A (cyano complex) NiCl ₂+ conc. HCl (excess) B (chloro complex) Question: Predict the magnetic nature of A and B are

Step-by-step solution

In it unpaired orbital is not present, so it is diamagnetic in character (square planar shape) In chloro complex K ₂ [ Ni ( Cl )₄ ] , complex ion is [ Ni ^2 ( Cl ₄ ) ]²⁻ and Ni is present Ni ²⁺ or Ni ( II ) , so Ni ^2+=1 s^2, 2 s^2 2 p^6, 3 s^2 3 p^6 3 d^8, 4 s^0 In . [ Ni _ ( Cl ₄ ) ) ]^2 ion, Ni ²⁺ is present as follows due to weaker ligand character is Cl ⁻ ion. ( Cl ⁻ . is weak field ligand). So, it is unable to pair up the electron and Ni ²⁺ needs four empty orbitals to accommodate four Cl ⁻ ligand. Thus, ( Ni