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JEE Advanced 2021Paper 1
Exam
JEE Advanced
Year
2021
Paper
Paper 1
Subject
Chemistry
Chapter
Practical Chemistry

JEE Advanced 2021 · Paper 1 · Chemistry · Practical Chemistry

A mixture of two salts is used to prepare a solution S, which gives...

A mixture of two salts is used to prepare a solution S,S, which gives the following results:

Whiteprecipitate\left(s\right)only\mathop{←}_{Roomtemperature}^{DiluteNaOH ( aq )}\mathop{S}_{\left(aq . solutionofthesalts\right)}\mathop{\to}_{Roomtemperature}^{DiluteHCl\left(aq\right)}Whiteprecipitate\left(s\right)only</p><p>Thecorrectoption(s)</p><p>The correct option \left(s\right) for the salt mixture is(are)

Options

  1. APb(NO3)2Pb{\left({NO}_{3}\right)}_{2} and Zn(NO3)2Zn{\left({NO}_{3}\right)}_{2}
  2. BPb(NO3)2Pb{\left({NO}_{3}\right)}_{2} and Bi(NO3)3Bi{\left({NO}_{3}\right)}_{3}
  3. C{AgNO}_{3}andandBi{\left({NO}_{3}\right)}_{3}
  4. DPb(NO3)2Pb{\left({NO}_{3}\right)}_{2} and Hg(NO3)2Hg{\left({NO}_{3}\right)}_{2}

Correct answer

A. Pb(NO3)2Pb{\left({NO}_{3}\right)}_{2} and Zn(NO3)2Zn{\left({NO}_{3}\right)}_{2}

Step-by-step solution

Pb2+→dil.HClPbCl2P{b}^{2 +}\overset{dil . HCl}{\to}{PbCl}_{2}(white precipitate)

Pb2+→dil.NaOHPb(OH)2P{b}^{2 +}\overset{dil . NaOH}{\to}Pb{\left(OH\right)}_{2}(white precipitate)

Bi3+→dilHClBiCl3{Bi}^{3 +}\overset{dilHCl}{\to}{BiCl}_{3}(water-soluble)

Bi3+→dil.NaOHBi(OH)3{Bi}^{3 +}\overset{dil . NaOH}{\to}Bi{\left(OH\right)}_{3}(white precipitate)

Hg2+→dil.HClHgCl2{Hg}^{2 +}\overset{dil . HCl}{\to}{HgCl}_{2}(water-soluble)

Hg2+→dil.NaOHHg(OH)2{Hg}^{2 +}\overset{dil . NaOH}{\to}Hg{\left(OH\right)}_{2}(yellow precipitate)

Ag+→dil.HClAgCl{Ag}^{+}\overset{dil . HCl}{\to}AgCl(white precipitate)

Ag+→dil.NaOHAgOH{Ag}^{+}\overset{dil . NaOH}{\to}AgOH(brown precipitate)

Zn2+→dil.HClZnCl2{Zn}^{2 +}\overset{dil . HCl}{\to}{ZnCl}_{2}(water-soluble)

Zn2+→dil.NaOHZn(OH)2{Zn}^{2 +}\overset{dil . NaOH}{\to}Zn{\left(OH\right)}_{2}(white precipitate)

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