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JEE Advanced 2013Paper 1
Exam
JEE Advanced
Year
2013
Paper
Paper 1
Subject
Chemistry
Chapter
Solid State

JEE Advanced 2013 · Paper 1 · Chemistry · Solid State

The arrangement of X - ions around A + ion in solid AX is given in...

The arrangement of X- ions around A+ ion in solid AX is given in the figure (not drawn to scale). If the radius of X- is 250 pm, the radius of A+ is 
The arrangement of X - ions around A + ion in solid AX is given in the figure (not drawn to scale). If the radius of X

Options

  1. A104 pm
  2. B125 pm
  3. C183 pm
  4. D57 pm

Correct answer

A. 104 pm

Step-by-step solution

A+ cation is filled in octahedral hole generated by X- anion
i.e., rA+rX−=0.414\dfrac{\text{r} {\text{A}}^{+}}{\text{r} {\text{X}}^{-}} = \text{0.414}
rA+=0.414×250=103.5pm\text{r} {\text{A}}^{+} = \text{0.414} \times 2 5 0 = \text{103.5} \text{pm}
≈104pm\approx 1 0 4 \text{pm}
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