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JEE Main 20146 April
Exam
JEE Main
Year
2014
Date
6 April
Subject
Chemistry
Chapter
Solid State

JEE Main 2014 · 6 April · Chemistry · Solid State

CsCl crystallises in body centred cubic lattice. If 'a' is its edge...

CsCl\text{CsCl} crystallises in body centred cubic lattice. If 'a' is its edge length then which of the following expressions is correct?CsCl crystallises in body centred cubic lattice. If 'a' is its edge length then which of the following expressions is

Options

  1. ArCs++rCl−=3a\text{r} {\text{Cs}}^{+} + \text{r} {\text{Cl}}^{-} = 3 \text{a}
  2. BrCs++rCl−=3a2\text{r} {\text{Cs}}^{+} + \text{r} {\text{Cl}}^{-} = \dfrac{3 \text{a}}{2}
  3. CrCs++rCl−=32a\text{r} {\text{Cs}}^{+} + \text{r} {\text{Cl}}^{-} = \dfrac{\sqrt{3}}{2} a
  4. DrCs++rCl−=3a\text{r} {\text{Cs}}^{+} + \text{r} {\text{Cl}}^{-} = \sqrt{3} \text{a}

Correct answer

C. rCs++rCl−=32a\text{r} {\text{Cs}}^{+} + \text{r} {\text{Cl}}^{-} = \dfrac{\sqrt{3}}{2} a

Step-by-step solution

8\text{8} chloride ions at 8\text{8} corners Cs+{\text{Cs}}^{+} cation at body centre along body diagonal there will be one Cs+{\text{Cs}}^{+} cation and 2Cl−\text{2}{\text{Cl}}^{−} ions at ends of body diagonal.
2rCs++2rCl−=3a2 \text{r} {Cs}^{+} + 2 \text{r} {Cl}^{-} = \sqrt{3} a
a\text{a} is edge length
CsCl crystallises in body centred cubic lattice. If 'a' is its edge length then which of the following expressions is
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