For the following reaction scheme, percentage yields are given along the arrow:

$\mathbf{x} g$ and $\mathbf{y} g$ are mass of $\mathbf{R}$ and $\mathbf{U}$ , respectively.
(Use: Molar mass (in $\mathrm{g} \mathrm{mol}^{-1}$ ) $of \mathrm{H}, \mathrm{C}$ and $\mathrm{O}$ as 1,12 and 16 , respectively)
The value of $y$ is ___.

Question

For the following reaction scheme, percentage yields are given along the arrow:

\mathbf{x} g

and

\mathbf{y} g

are mass of

\mathbf{R}

and

\mathbf{U}

, respectively.
(Use: Molar mass (in

\mathrm{g} \mathrm{mol}^{-1}

)

of \mathrm{H}, \mathrm{C}

and

\mathrm{O}

as 1,12 and 16 , respectively)
The value of

y

is ___.

Quantrex Academy · Accepted Answer

Correct answer: 0

Mg _ 2 C _ 3 H _ 2 O → Mg ( OH ) _ 2 + C _ 3 H _ 4 ( P ) _ Propyne ( 4g ) CH _ 3 - C ≡ CH→ array ll 33K ( 100% ) array Hg ^ 2 + CH _ 3 - C _ | | _ O - CH _ 3 _ ( S ) Now, one moe of propyne give one mole of acetone. (100 %) . one mole of acetone give 0 . 5 moles of α, β -unsaturated compound [100 % yield] . But given that 80 % yield. No. of moles of α, β -unsaturated compound = 0 .04 mol . = 0 .04 mol of (T) can give = 0 .04 mol of (U) [100 % yield]. But given that 80 %yield. No. of moles of (U) formed = 0 . 032 mass of (U) formed 0.032 × 100 = 3 . 20

For the following reaction scheme, percentage yields are given...

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