For the following reaction scheme, percentage yields are given along the arrow: x g and y g are mass of R and U , respectively. (Use: Molar mass (in g mol ⁻¹ ) of H , C and O as 1,12 and 16 , respectively) The value of y is ___.

Step-by-step solution

Mg 2 C 3 → H 2 O Mg ( OH ) 2 + C 3 H 4 ( P ) Propyne   ( 4 g ) CH 3 − C ≡ CH → 33 K ( 100 % ) Hg 2 + CH 3 − C | | O − CH 3 ( S ) Now, one moe of propyne give one mole of acetone. 100 % . one mole of acetone give 0 . 5 moles of α , β -unsaturated compound 100 %   yield . But given that 80 % yield. No. of moles of α , β -unsaturated compound = 0 .04   mol . = 0 .04   mol of T can give = 0 .04   mol of U 100 %   yield . But given tha