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JEE Main 20211 SeptemberEvening Shift
Exam
JEE Main
Year
2021
Date
1 September
Shift
Evening Shift
Subject
Chemistry
Chapter
Some Basic Concepts of Chemistry

JEE Main 2021 · 1 September · Evening Shift · Chemistry · Some Basic Concepts of Chemistry

The number of atoms in 8g of sodium is x × 10 ^ 23 . The value of x...

The number of atoms in 8g8g of sodium is x×1023.x \times {10}^{23} . The value of xx is _____ . (Nearest integer)

\left[\text{Given :}{N}_{A} = 6 . 02 \times {10}^{23}{mol}^{- 1}\right\text{Atomic mass of}Na = 23 . 0u ]$

Correct answer

0

Step-by-step solution

Number of mole of sodium =[823]= \left[\dfrac{8}{23}\right]

Number of sodium atom =[823]×6×1023=2.08×1023= \left[\dfrac{8}{23}\right] \times 6 \times {10}^{23} = 2 . 08 \times {10}^{23}

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