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JEE Advanced 2019Paper 2
Exam
JEE Advanced
Year
2019
Paper
Paper 2
Subject
Chemistry
Chapter
Some Basic Concepts of Chemistry

JEE Advanced 2019 · Paper 2 · Chemistry · Some Basic Concepts of Chemistry

The mole fraction of urea in an aqueous urea solution containing...

The mole fraction of urea in an aqueous urea solution containing 900g900g of water is 0.050.05 . If the density of the solution is 1.2gcm−31.2g{cm}^{- 3} , the molarity of urea solution is _______
(Given data: Molar masses of urea and water are 60gmol−160g{mol}^{- 1} and 18gmol−118g{mol}^{- 1} , respectively)

Correct answer

0

Step-by-step solution

Mole fraction ⇒0.05⇒ 0.05
Number of moles of water ⇒90018=50⇒ \dfrac{900}{18} = 50
∴nureanurea+50=0.05∴ \dfrac{{n}_{urea}}{{n}_{urea} + 50} = 0.05
nurea=2.63{n}_{urea} = 2.63
Mass of urea =(Wurea)=2.63×60⇒157.8g= \left({W}_{urea}\right) = 2.63 \times 60 ⇒ 157.8g
Total mass of solution ⇒157.8+900⇒1057.8g⇒ 157.8 + 900 ⇒ 1057.8g
Volume of solution ⇒1057.81.2ml⇒881.5ml⇒ \dfrac{1057.8}{1.2}ml ⇒ 881.5ml
Molarity ⇒no.ofmolesofsolutionsvolumeofsolutioninL⇒2.630.8815⇒2.98M⇒ \dfrac{no . ofmolesofsolutions}{volumeofsolutioninL} ⇒ \dfrac{2.63}{0.8815} ⇒ 2.98M
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