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JEE Main 201912 AprilEvening Shift
Exam
JEE Main
Year
2019
Date
12 April
Shift
Evening Shift
Subject
Chemistry
Chapter
Some Basic Concepts of Chemistry

JEE Main 2019 · 12 April · Evening Shift · Chemistry · Some Basic Concepts of Chemistry

25g of an unknown hydrocarbon upon burnig produces 88g of C O _ 2...

25g25g of an unknown hydrocarbon upon burnig produces 88g88g of CO2C{O}_{2} and 9g9g of H2O.{H}_{2}O . This unknown hydrocarbon contains:25g of an unknown hydrocarbon upon burnig produces 88g of C O _ 2 and 9g of H _ 2 O . This unknown hydrocarbon contains:

Options

  1. A24g24g of carbon and 1g1g of hydrogen
  2. B18g18g of carbon annd 7g7g of hydrogen
  3. C22g22g of carbon and 3g3g of hydrogen
  4. D20g20g carbon and 5g5g of hydrogen

Correct answer

A. 24g24g of carbon and 1g1g of hydrogen

Step-by-step solution

25g of an unknown hydrocarbon upon burnig produces 88g of C O _ 2 and 9g of H _ 2 O . This unknown hydrocarbon contains:
2mole2mole of CO2C{O}_{2} contains 2mole2mole of carbon, Hence weight of carbon =2×12=24g= 2 \times 12 = 24g .
mass of Hydrogen =25−24=1gram= 25 - 24 = 1gram
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