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JEE Advanced 2015Paper 1
Exam
JEE Advanced
Year
2015
Paper
Paper 1
Subject
Chemistry
Chapter
Some Basic Concepts of Chemistry

JEE Advanced 2015 · Paper 1 · Chemistry · Some Basic Concepts of Chemistry

The % yield of ammonia as a function of time in the reaction N _ 2...

The % yield of ammonia as a function of time in the reaction
N2(g)+3H2(g)⇌2NH3(g),\DeltaH<0{N}_{2}\left(g\right) + 3{H}_{2}\left(g\right) ⇌ 2N{H}_{3}\left(g\right), \DeltaH < 0 at (P,T1)( P, {T}_{1} ) is given below.

The % yield of ammonia as a function of time in the reaction N _ 2 (g) + 3 H _ 2 (g) ⇌ 2N H _ 3 (g), If this reaction
If this reaction is conducted at (P,T2)( P, {T}_{2} ) with T2>T1{T}_{2} > {T}_{1} , the % yield of ammonia as a function of time is represented by:

Options

  1. AThe rate constant k , for the reaction N_ 2 O_ 5( g) arrow2 NO_ 2( g) +1 / 2 O_ 2( g) is 2.3 ×10^ -2 s^ -1 . Which
  2. BThe rate constant k , for the reaction N_ 2 O_ 5( g) arrow2 NO_ 2( g) +1 / 2 O_ 2( g) is 2.3 ×10^ -2 s^ -1 . Which
  3. CThe rate constant k , for the reaction N_ 2 O_ 5( g) arrow2 NO_ 2( g) +1 / 2 O_ 2( g) is 2.3 ×10^ -2 s^ -1 . Which
  4. DThe rate constant k , for the reaction N_ 2 O_ 5( g) arrow2 NO_ 2( g) +1 / 2 O_ 2( g) is 2.3 ×10^ -2 s^ -1 . Which

Correct answer

B. The rate constant k , for the reaction N_ 2 O_ 5( g) arrow2 NO_ 2( g) +1 / 2 O_ 2( g) is 2.3 ×10^ -2 s^ -1 . Which

Step-by-step solution

Initially on increasing temperature rate of reaction will increase, so % yield will also increase with time. But at equilibrium % yield at high temperature (T2)( {T}_{2} ) would be less than at T1{T}_{1} as reaction is exothermic so the graph is

The % yield of ammonia as a function of time in the reaction N _ 2 (g) + 3 H _ 2 (g) ⇌ 2N H _ 3 (g), If this reaction

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