In the following reaction: A + 2 B + 3 C ⇌ A B 2 C 3 6 . 0   g of A , 6.0 × 10 23   atoms of B and 0 . 036   mol of C reacted and formed 4 . 8   g of compound A B 2 C 3 . If the atomic mass of A and C are 60 and 80   amu , respectively. What is the atomic mass of B in amu ? (Avogadro number = 6 × 10 23 )

Step-by-step solution

A + 2 B + 3 C → AB 2 C 3 6 g 6 × 1 0 2 3 atoms 0.036 moles Moles 6 6 0 6 × 1 0 2 3 6 × 1 0 2 3 0.1 mole 1.0 mole 0.036 moles 0.1 1   , 1.0 2   , 0.036 3 ;   t h e   l e a s t   v a l u e   i s   0.012 ,   i . e . ,   C   i s   the   li m i t i n g   re a g e n t 0 . 036   moles of C provides 0 . 012   moles of A B 2 C 3 . 0 . 012   moles of A B 2 C 3 weighs 4 .8   g 1   mole of AB 2 C 3 weighs 4 .8 0 .012