JEE Main 201511 AprilOnline
- Exam
- JEE Main
- Year
- 2015
- Date
- 11 April
- Mode
- Online
- Subject
- Chemistry
- Chapter
- Some Basic Concepts of Chemistry
JEE Main 2015 · 11 April · Online · Chemistry · Some Basic Concepts of Chemistry
In the following reaction: A + 2B + 3C ⇌ A B _ 2 C _ 3 6 . 0g of A...
In the following reaction:
of , atoms of and of reacted and formed of compound . If the atomic mass of and are and , respectively. What is the atomic mass of in ? (Avogadro number)
Options
- A
- B
- C
- D
Correct answer
D.
Step-by-step solution
\begin{cases} & \text{A} & + & 2 \text{B} & + & 3 \text{C} & \to & {\text{AB}_{2} {\text{C}_{3} \\ & 6 \text{g} & & 6 \times 1 {0}^{2 3} \text{atoms} & & \text{0.036} moles & & \\ \text{Moles} & \dfrac{6}{6 0} & & \dfrac{6 \times 1 {0}^{2 3}}{6 \times 1 {0}^{2 3}} & & & & \\ & \text{0.1 mole} & & \text{1.0 mole} & & \text{0.036 moles} & & \end{cases}
\left(\dfrac{0.1}{1}, \dfrac{1.0}{2}, \dfrac{0.036}{3}; theleastvalueis0.012, i . e . , Cisthelimitingreagent\right)0 . 036moles of C0 . 012moles of A{B}_{2}{C}_{3}0 . 012moles of A{B}_{2}{C}_{3}4 .8 g1mole of {AB}_{2}{C}_{3}\dfrac{4 .8}{0 .012} = 400g{mol}^{- 1}400 = 60 + 2B + 3 \times 80B = 50amu
\left(\dfrac{0.1}{1}, \dfrac{1.0}{2}, \dfrac{0.036}{3}; theleastvalueis0.012, i . e . , Cisthelimitingreagent\right)0 . 036moles of C0 . 012moles of A{B}_{2}{C}_{3}0 . 012moles of A{B}_{2}{C}_{3}4 .8 g1mole of {AB}_{2}{C}_{3}\dfrac{4 .8}{0 .012} = 400g{mol}^{- 1}400 = 60 + 2B + 3 \times 80B = 50amu