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JEE Advanced 2014Paper 1

Exam: JEE Advanced
Year: 2014
Paper: Paper 1
Subject: Chemistry
Chapter: Some Basic Concepts of Chemistry

JEE Advanced 2014 · Paper 1 · Chemistry · Some Basic Concepts of Chemistry

A compound H _ 2 X with molar weight of 80g is dissolved in a...

A compound

{H}_{2}X

with molar weight of 80g is dissolved in a solvent having density of

0.4gm{l}^{– 1}

. Assuming no change in volume upon dissolution, the molality of a 3.2 molar solution is

Correct answer

8

Step-by-step solution

Here,

{V}_{solution} \approx {V}_{solvent}

Since, in

1l

solution, 3.2 moles of solute are present,
So,

1l

solution

\approx 1l

solvent (d = 0.4g/ml)

\approx

0.4 kg
So, molality (m)

= \dfrac{Molesofsolute}{Massofsolvent ( kg )} = \dfrac{3.2}{0.4} = 8

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