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JEE Advanced2014ChemistrySome Basic Concepts of ChemistryActual

A compound H 2 X with molar weight of 80g is dissolved in a solvent having density of 0.4 g m l – 1 . Assuming no change in volume upon dissolution, the molality of a 3.2 molar solution is

Correct answer

8

Step-by-step solution

Here, V s o l u t i o n ≈ V s o l v e n t Since, in 1 l solution, 3.2 moles of solute are present, So, 1 l solution ≈ 1 l solvent (d = 0.4g/ml) ≈ 0.4 kg So, molality (m) = M o l e s o f s o l u t e M a s s o f s o l v e n t ( k g ) = 3.2 0.4 = 8

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