The molecular formula of a commercial resin used for exchanging ions in water softening is C _ 8 H _ 7 S O _ 3 Na (molecularweight = 206). What would be the maximum uptake of C a ^ 2 + ions by the resin if expressed in

Correct answer: A. (1)/(412) 2 C _ 8 H _ 7 SO _ 3 Na(aq) + Ca ^ 2 + (aq) → ( C _ 8 H _ 7 SO _ 3 ) _ 2 Ca(aq) + 2 Na ^ + (aq) 1 mol calcium ion reacts with 2 moles of resin 2mol(resin) = 412 g resin ≡ 40g Ca ^ 2 + ions = 1molof Ca ^ 2 + ions ∴ Molesof Ca ^ 2 + per gofresin = (1)/(412)

JEE Main 20154 April

Exam: JEE Main
Year: 2015
Date: 4 April
Subject: Chemistry
Chapter: Some Basic Concepts of Chemistry

JEE Main 2015 · 4 April · Chemistry · Some Basic Concepts of Chemistry

The molecular formula of a commercial resin used for exchanging...

The molecular formula of a commercial resin used for exchanging ions in water softening is

{C}_{8}{H}_{7}S{O}_{3}Na \left(molecularweight = 206\right). What would be

the maximum uptake of C{a}^{2 +}

ions by the resin if expressed in

mol

per

?

Options

A $\dfrac{1}{412}$
B $\dfrac{1}{103}$
C $\dfrac{1}{206}$
D $\dfrac{2}{309}$

Correct answer

A. $\dfrac{1}{412}$

Step-by-step solution

$2{C}_{8}{H}_{7}{SO}_{3}Na\left(aq\right) + {Ca}^{2 +}\left(aq\right) \to {\left({C}_{8}{H}_{7}{SO}_{3}\right)}_{2}Ca\left(aq\right) + 2{Na}^{+}\left(aq\right)$

1 mol calcium ion reacts with 2 moles of resin

$2mol\left(resin\right) = 412 g resin ≡ 40g{Ca}^{2 +}ions$
$= 1molof{Ca}^{2 +} ions$
$∴ Molesof{Ca}^{2 +}$ per $gofresin$ $= \dfrac{1}{412}$

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