JEE Advanced 2018Paper 1
- Exam
- JEE Advanced
- Year
- 2018
- Paper
- Paper 1
- Subject
- Mathematics
- Chapter
- Limits
JEE Advanced 2018 · Paper 1 · Mathematics · Limits
For each positive integer n , let y _ n = (1)/(n) ( ( n + 1 )( n +...
For each positive integer , let . If then the value of \left[L\right] is the greatest integer less than or equal to ) is ____
Correct answer
0
Step-by-step solution
{y}_{n} = {\left\{\left(1 + \dfrac{1}{n}\right)\left(1 + \dfrac{2}{n}\right) \ldots . \left(1 + \dfrac{n}{n}\right)\right\}}^{\dfrac{1}{n}}{y}_{n} = \mathop{∏}_{r = 1}^{n}{\left(1 + \dfrac{r}{n}\right)}^{\dfrac{1}{n}}\ln \left({y}_{n}\right) = \dfrac{1}{n}\mathop{∑}_{r = 1}^{n}\ln \left(1 + \dfrac{r}{n}\right)⇒ \lim_{n \to \infty} \ln ( {y}_{n} ) = \lim_{n \to \infty} \mathop{∑}_{r = 1}^{n}\dfrac{1}{n}\ln \left(1 + \dfrac{r}{n}\right)⇒ \ln \left(L\right) = {∫}_{0}^{1}\ln \left(1 + x\right)dx⇒ \ln \left(L\right) = \ln \left(\dfrac{4}{e}\right)⇒ L = \dfrac{4}{e}