JEE Main2018MathematicsLimitsActual
lim x → 0 ( 27 + x ) 1 3 - 3 9 - ( 27 + x ) 2 3 equals
Options
- A- 1 6
- B  1 6
- C  1 3
- D- 1 3
Correct answer
A. - 1 6
Step-by-step solution
Given limit is lim x → 0 27 + x 1 3 - 3   9 - 27 + x 2 3       0 0   f o r m Applying L'Hospital's rule, ⇒ l i m x → 0   1 3 27 + x - 2 3   - 2 3 27 + x - 1 3 = 27 - 2 3 - 2 27 - 1 3 = - 1 2 27 1 3   = - 1 6 .