JEE Main 202311 AprilEvening Shift
- Exam
- JEE Main
- Year
- 2023
- Date
- 11 April
- Shift
- Evening Shift
- Subject
- Chemistry
- Chapter
- Alcohols Phenols and Ethers
JEE Main 2023 · 11 April · Evening Shift · Chemistry · Alcohols Phenols and Ethers
Product [X] formed in the above reaction is:
Product formed in the above reaction is:
Options
- A
![The dibromo compound [P] (molecular formula : C_ 9 H_ 10 Br_ 2 ) when heated with excess sodamide followed by treatment](/api/proxy-image?url=https%3A%2F%2Ffirebasestorage.googleapis.com%2Fv0%2Fb%2Fquantrexacademy-app.firebasestorage.app%2Fo%2Fquestions%252Ffigs%252Fpyq%252Fjee_main%252F86cdac59-72a6-41d1-b98c-9d615298ef68.png%3Falt%3Dmedia&clean=1&v=qxfig138)
- B
![The dibromo compound [P] (molecular formula : C_ 9 H_ 10 Br_ 2 ) when heated with excess sodamide followed by treatment](/api/proxy-image?url=https%3A%2F%2Ffirebasestorage.googleapis.com%2Fv0%2Fb%2Fquantrexacademy-app.firebasestorage.app%2Fo%2Fquestions%252Ffigs%252Fpyq%252Fjee_main%252Fdbb629d8-ba82-40de-95f3-7dde02b4de27.png%3Falt%3Dmedia&clean=1&v=qxfig138)
- C
![The dibromo compound [P] (molecular formula : C_ 9 H_ 10 Br_ 2 ) when heated with excess sodamide followed by treatment](/api/proxy-image?url=https%3A%2F%2Ffirebasestorage.googleapis.com%2Fv0%2Fb%2Fquantrexacademy-app.firebasestorage.app%2Fo%2Fquestions%252Ffigs%252Fpyq%252Fjee_main%252F00674ef0-7f43-450b-bed3-6bb3c08cceba.png%3Falt%3Dmedia&clean=1&v=qxfig138)
- D
![The dibromo compound [P] (molecular formula : C_ 9 H_ 10 Br_ 2 ) when heated with excess sodamide followed by treatment](/api/proxy-image?url=https%3A%2F%2Ffirebasestorage.googleapis.com%2Fv0%2Fb%2Fquantrexacademy-app.firebasestorage.app%2Fo%2Fquestions%252Ffigs%252Fpyq%252Fjee_main%252F30d49cb2-bab2-43ee-b296-fe665a0b6bc7.png%3Falt%3Dmedia&clean=1&v=qxfig138)
Correct answer
C. ![The dibromo compound [P] (molecular formula : C_ 9 H_ 10 Br_ 2 ) when heated with excess sodamide followed by treatment](/api/proxy-image?url=https%3A%2F%2Ffirebasestorage.googleapis.com%2Fv0%2Fb%2Fquantrexacademy-app.firebasestorage.app%2Fo%2Fquestions%252Ffigs%252Fpyq%252Fjee_main%252F00674ef0-7f43-450b-bed3-6bb3c08cceba.png%3Falt%3Dmedia&clean=1&v=qxfig138)
Step-by-step solution
The alcohol is reacted with a mixture of sodium iodide and concentrated phosphoric acid, , and the iodoalkane is distilled off. The 2-iodobutane formed in the previous reaction give Grignard reagent with magnesium metal in dry ether. The Grignard reagent formed reacts with to give 2-deuterobutane.