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JEE Main 20268 AprilEvening Shift
Exam
JEE Main
Year
2026
Date
8 April
Shift
Evening Shift
Subject
Chemistry
Chapter
Amines

JEE Main 2026 · 8 April · Evening Shift · Chemistry · Amines

Which statements are True? A. In Hoffmann bromamide degradation, 4...

Which statements are True?
A. In Hoffmann bromamide degradation, 44 moles of NaOH and 22 moles of Br2_2 are consumed per mole of an amide
B. Hoffmann bromamide reaction is not given by alkyl amides.
C. Primary amines can be synthesized by Hoffmann bromamide degradation.
D. Secondary amide on reaction with Br2_2 and NaOH will give secondary amine.
E. The by-products of Hoffmann degradation are Na2_2CO3_3, NaBr and H2_2O.
Choose the correct answer from the options given below:

Options

  1. AA, C and E only
  2. BB, C and D only
  3. CC and E only
  4. DC, D and E only

Correct answer

C. C and E only

Step-by-step solution

The balanced chemical equation for Hoffmann bromamide degradation is:

R-CONH2+Br2+4NaOH→R-NH2+Na2CO3+2NaBr+2H2O\text{R-CONH}_2 + \text{Br}_2 + 4\text{NaOH} \rightarrow \text{R-NH}_2 + \text{Na}_2\text{CO}_3 + 2\text{NaBr} + 2\text{H}_2\text{O}

Statement A is false because 11 mole of Br2\text{Br}_2 and 44 moles of NaOH\text{NaOH} are consumed per mole of amide.

Statement B is false because primary alkyl amides readily undergo this reaction.

Statement C is true as the primary product of this reaction is a primary amine.

Statement D is false because the reaction is strictly given by primary amides (R-CONH2\text{R-CONH}_2), not secondary amides.

Statement E is true as the by-products formed are Na2CO3\text{Na}_2\text{CO}_3, NaBr\text{NaBr}, and H2O\text{H}_2\text{O}.

Therefore, only statements C and E are true.

Answer: C and E only
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