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JEE Main 20265 AprilEvening Shift
Exam
JEE Main
Year
2026
Date
5 April
Shift
Evening Shift
Subject
Chemistry
Chapter
Amines

JEE Main 2026 · 5 April · Evening Shift · Chemistry · Amines

Given below are two statements : Statement I: Heating benzamide...

Given below are two statements :
Statement I: Heating benzamide with bromine in an ethanolic solution of sodium hydroxide will give benzylamine.
Statement II: Nitration of aniline with HNO3/H2SO4HNO_3/H_2SO_4 at 288 K288\text{ K} produces mm-nitroaniline in higher amount than oo-nitroaniline (pH adjusted).
In the light of the above statements, choose the correct answer from the options given below :

Options

  1. ABoth Statement I and Statement II are true
  2. BBoth Statement I and Statement II are false
  3. CStatement I is true but Statement II is false
  4. DStatement I is false but Statement II is true

Correct answer

D. Statement I is false but Statement II is true

Step-by-step solution

Statement I describes the Hoffmann bromamide degradation reaction. When benzamide (C6H5CONH2C_6H_5CONH_2) is heated with bromine in an ethanolic solution of sodium hydroxide, it produces aniline (C6H5NH2C_6H_5NH_2), not benzylamine. Thus, Statement I is false.

Statement II describes the nitration of aniline. Direct nitration of aniline with HNO3/H2SO4HNO_3/H_2SO_4 yields a mixture of pp-nitroaniline (51%51\%), mm-nitroaniline (47%47\%), and oo-nitroaniline (2%2\%). The significant formation of the meta derivative is due to the protonation of aniline in the strongly acidic medium to form the anilinium ion, which is meta-directing. Since 47%>2%47\% > 2\%, mm-nitroaniline is produced in a higher amount than oo-nitroaniline. Thus, Statement II is true.

Answer: Statement I is false but Statement II is true
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