Consider the following organic reaction sequence. Choose the final...

The starting material is propanoic acid ($CH_3CH_2COOH$).

In step (i), propanoic acid reacts with $NH_3$ upon heating to form propanamide.
$CH_3CH_2COOH \xrightarrow{NH_3, \Delta} CH_3CH_2CONH_2$

In step (ii), propanamide undergoes Hoffmann bromamide degradation with $NaOH$ and $Br_2$ to form ethylamine.
$CH_3CH_2CONH_2 \xrightarrow{NaOH, Br_2} CH_3CH_2NH_2$

In step (iii), ethylamine reacts with nitrous acid ($HNO_2$) to form an unstable diazonium salt, which hydrolyzes to give ethanol.
$CH_3CH_2NH_2 \xrightarrow{HNO_2, H_2O} CH_3CH_2OH$

In step (iv), ethanol reacts with benzenediazonium chloride ($C_6H_5N_2Cl$). Ethanol reduces the diazonium salt to benzene, while getting oxidized to ethanal.
$CH_3CH_2OH + C_6H_5N_2Cl \rightarrow C_6H_6 + CH_3CHO + N_2 + HCl$

The final major product (X) is benzene.

Answer: Benzene