Consider the following data for the given reaction 2 HI ( g ) → H 2 ( g ) + I 2 ( g ) HI molL - 1 0 . 005 0 . 01 0 . 02 Rate molL - 1 s - 1 7 . 5 × 10 - 4 3 . 0 × 10 - 3 1 . 2 × 10 - 2 The order of the reaction is __________.

Step-by-step solution

The initial concentrations of HI as 0 . 005 , 0 . 01 , and 0 . 02 mol/L, respectively, and the corresponding initial rates as given: HI molL - 1 0 . 005 0 . 01 0 . 02 Rate molL - 1 s - 1 7 . 5 × 10 - 4 3 . 0 × 10 - 3 1 . 2 × 10 - 2 For the reaction, rate law is rate = k HI P P is the order of the reaction. From the given data 7 . 5 × 10 - 4 = k 0 . 05 P -------(1) 3 × 10 - 3 = k 0 . 01 P --------(2) 1 . 2 × 10 - 2 = k 0 . 02 P ---------(3) On dividing Equation (3) by equation (2) 12 × 10 - 3 3 × 10 - 3 = k 0 . 02 P