For the adsorption of hydrogen on platinum, the activation energy...

According to Arrhenius's equation,

$k = {Ae}^{- {E}_{a} / RT}logk = logA - \dfrac{{E}_{a}}{2 . 3RT}$

${E}_{a1} =$For the adsorption of hydrogen on platinum, the activation energy

${E}_{a2} =$for the adsorption of hydrogen on nickel, the activation energy

$\log \left(\dfrac{{k}_{2}}{{k}_{1}}\right) = \dfrac{{E}_{a2} - {E}_{a1}}{2 . 3RT}$$= \dfrac{11 . 4 \times 1000}{2 . 3 \times 8 . 3 \times 300}$

$= 1 . 990 \approx 2$