JEE Main20236 Apr 2023Morning ShiftChemistryChemical KineticsActual
For the adsorption of hydrogen on platinum, the activation energy is 30   kJ   mol – 1 and for the adsorption of hydrogen on nickel, the activation energy is 41 . 4   kJ   mol – 1 . The logarithm of the ratio of the rates of chemisorption on equal areas of the metals at 300   K is _ _ _ _ _ _ _ (Nearest integer) Given: In 10 = 2 . 3 R = 8 . 3   J   K - 1   mol - 1
Correct answer
0
Step-by-step solution
According to Arrhenius's equation, k = Ae - E a / RT logk = logA - E a 2 . 3 RT E a 1 = For the adsorption of hydrogen on platinum, the activation energy E a 2 = for the adsorption of hydrogen on nickel, the activation energy log k 2   k 1 = E a 2 - E a 1 2 . 3   RT = 11 . 4 × 1000 2 . 3 × 8 . 3 × 300 = 1 . 990 ≈ 2