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JEE Main 20231 FebruaryEvening Shift
Exam
JEE Main
Year
2023
Date
1 February
Shift
Evening Shift
Subject
Chemistry
Chapter
Chemical Kinetics

JEE Main 2023 · 1 February · Evening Shift · Chemistry · Chemical Kinetics

The graph which represents the following reaction is: ( C _ 6 H _ 5...

The graph which represents the following reaction is:

(C6H5)3C−ClOH−Pyridine(C6H5)3C−OH{\left({C}_{6}{H}_{5}\right)}_{3}C - Cl\dfrac{{OH}^{-}}{Pyridine}{\left({C}_{6}{H}_{5}\right)}_{3}C - OH

The graph which represents the following reaction is: ( C _ 6 H _ 5 ) _ 3 C - Cl OH ^ - Pyridine ( C _ 6 H _ 5 ) _ 3 CThe graph which represents the following reaction is: ( C _ 6 H _ 5 ) _ 3 C - Cl OH ^ - Pyridine ( C _ 6 H _ 5 ) _ 3 CThe graph which represents the following reaction is: ( C _ 6 H _ 5 ) _ 3 C - Cl OH ^ - Pyridine ( C _ 6 H _ 5 ) _ 3 CThe graph which represents the following reaction is: ( C _ 6 H _ 5 ) _ 3 C - Cl OH ^ - Pyridine ( C _ 6 H _ 5 ) _ 3 C

Options

  1. AWhich one of the following statements is correct when S O _ 2 is passed through acidified K _ 2 C r _ 2 O _ 7 solution?
  2. BWhich one of the following statements is correct when S O _ 2 is passed through acidified K _ 2 C r _ 2 O _ 7 solution?
  3. CWhich one of the following statements is correct when S O _ 2 is passed through acidified K _ 2 C r _ 2 O _ 7 solution?
  4. DWhich one of the following statements is correct when S O _ 2 is passed through acidified K _ 2 C r _ 2 O _ 7 solution?

Correct answer

C. Which one of the following statements is correct when S O _ 2 is passed through acidified K _ 2 C r _ 2 O _ 7 solution?

Step-by-step solution

Given reaction,

(C6H5)3C−ClOH−Pyridine(C6H5)3C−OH{\left({C}_{6}{H}_{5}\right)}_{3}C - Cl\dfrac{{OH}^{-}}{Pyridine}{\left({C}_{6}{H}_{5}\right)}_{3}C - OH

It is SN1{S}_{N}1 reaction. So rate of reaction depends on the concentration of alkyl halide only.

So, the correct graph is option (C).

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