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JEE Main 202331 JanuaryEvening Shift
Exam
JEE Main
Year
2023
Date
31 January
Shift
Evening Shift
Subject
Chemistry
Chapter
Chemical Kinetics

JEE Main 2023 · 31 January · Evening Shift · Chemistry · Chemical Kinetics

The rate constant for a first order reaction is 20 ^ - 1 . The time...

The rate constant for a first order reaction is 20min⁡−120\min^{- 1}. The time required for the initial concentration of the reactant to reduce to its 132\dfrac{1}{32} level is ______ \times {10}^{- 2}min. (Nearest integer)

Correct answer

0

Step-by-step solution

For a first order reaction, we know:
t1/2=0.693k=0.69320=0.03465min{t}_{1/2} = \dfrac{0 . 693}{k} = \dfrac{0 . 693}{20} = 0 . 03465min
From the relation of half lives(where 'n' is the no. of half-lives):

⇒(12)n=(132)⇒ {\left(\dfrac{1}{2}\right)}^{n} = \left(\dfrac{1}{32}\right)

=(12)5= {\left(\dfrac{1}{2}\right)}^{5}

Thus, No. of Half life =5= 5

∴∴Time required =0.03465×5=0.17325min=17.325×10−2min= 0 . 03465 \times 5 = 0 . 17325min = 17 . 325 \times {10}^{- 2}min

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