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JEE Main 202226 JuneEvening Shift
Exam
JEE Main
Year
2022
Date
26 June
Shift
Evening Shift
Subject
Chemistry
Chapter
Chemical Kinetics

JEE Main 2022 · 26 June · Evening Shift · Chemistry · Chemical Kinetics

Catalyst A reduces the activation energy for a reaction by 10kJ mol...

Catalyst A reduces the activation energy for a reaction by 10kJmol−110kJ{mol}^{- 1} at 300K300K. The ratio of rate constants, kT,CatalysedkT,Uncatalysed\dfrac{{k}_{T}, Catalysed}{{k}_{T}, Uncatalysed} is ex{e}^{x}. The value of xx is____[nearest integer] [Assume that the pre-exponential factor is same in both the cases. Given R=8.31JK−1mol−1R = 8 . 31J{K}^{- 1}{mol}^{- 1}]

Correct answer

0

Step-by-step solution

Arrhenius equation for the rate constant of a reaction in terms of energy of activation is given by

K=Ae−EaRTK = {Ae}^{- \dfrac{Ea}{RT}}

Kcatalyst=AeEa′RT{K}_{catalyst} = Ae\dfrac{Ea '}{RT}

Kuncatalysed=Ae−EaRT{K}_{uncatalysed} = {Ae}^{- \dfrac{Ea}{RT}}

KcatalystKUncatalysed=eEa−Ea′RT=e10×10008.314×300=e4\dfrac{{K}_{catalyst}}{{K}_{Uncatalysed}} = e\dfrac{Ea - {E}_{a}^{'}}{RT} = e\dfrac{10 \times 1000}{8 . 314 \times 300} = {e}^{4}

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