For a given chemical reaction γ 1 A + γ 2 B → γ 3 C + γ 4 D . Concentration of C changes from 10 mmol dm - 3 to 20 mmol dm - 3 in 10 s . Rate of appearance of D is 1 . 5 times the rate of disappearance of B which is twice the rate of disappearance A . The rate of appearance of D has been experimentally determined to be 9 mmol dm - 3 s - 1 . Therefore the rate of reaction is____ mmol dm - 3 s

Step-by-step solution

d c dt = 20 - 10 10 = 1 milimole / dm 3 sec γ 1 A + γ 2 B → γ 3 C + γ 4 D d D dt = 1 . 5 - d dt B = 9   milimole / dm 3   sec - d dt B = 2 - d dt A Rate = - 1 γ 1 d A dt = - 1 γ 2 d B dt = 1 γ 3 d C dt = 1 γ 4 d D dt (i) d D dt = γ 4 γ 2 - d B dt = 1 . 5 - d dt B γ 4 γ 2 = 1 . 5 (ii) γ 2 γ 1 - d A dt = - d dt B = 2 - d dt A γ 2 γ 1 = 2 (iii) d C dt = γ 3 γ 4 d D dt 1 = γ 3 γ 4 × 9 γ 4 γ