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JEE Main202224 Jun 2022Evening ShiftChemistryChemical KineticsActual

For a first order reaction, the time required for completion of 90 % reaction is ' x ' times the half life of the reaction. The value of ' x ' is (Given: ln 10 = 2 . 303 and log 2 = 0 . 3010 )

Options

  1. A1.12
  2. B2.43
  3. C3.32
  4. D33.31

Correct answer

C. 3.32

Step-by-step solution

ln 2 t 1 / 2 t 90 % = ln 100 10 = ln 10 t 90 % × 0 .693 t 1 / 2 = 2 .303 t 90 % = 2 . 303 0693 × t 1 / 2 = 3 .32 t 1 / 2 Hence, x = 3 . 32

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