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JEE Main202127 Aug 2021Morning ShiftChemistryChemical KineticsActual

The kinetic energy of an electron in the second Bohr orbit of a hydrogen atom is equal to h 2 x ma 0 2 . The value of 10 x is ( a 0 is radius of Bohr's orbit) (Nearest integer) [Given: π = 3 . 14 ]

Correct answer

0

Step-by-step solution

x = 8 π 2 × 16 4 = 32 π 2 = 32 ( 3 . 14 ) 2 = 315 . 5072 10 x = 315 . 5072

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