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JEE Main 20204 SeptemberEvening Shift
Exam
JEE Main
Year
2020
Date
4 September
Shift
Evening Shift
Subject
Chemistry
Chapter
Chemical Kinetics

JEE Main 2020 · 4 September · Evening Shift · Chemistry · Chemical Kinetics

The number of molecules with energy greater than the threshold...

The number of molecules with energy greater than the threshold energy for a reaction increases five fold by a rise of temperature from 27oC{27}^{o}C to 42oC{42}^{o}C. Its energy of activation in J/molJ / mol is _________ (Take ln⁡5=1.6094;R=8.314Jmol−1\ln 5 = 1 . 6094; R = 8 . 314J{mol}^{- 1})

Correct answer

0

Step-by-step solution

k=Ae−EaRTk = {Ae}^{-}\dfrac{Ea}{RT}

ln⁡(K2K1)=EaR[1T1−1T2]\ln \left(\dfrac{{K}_{2}}{{K}_{1}}\right) = \dfrac{Ea}{R}\left[\dfrac{1}{{T}_{1}} - \dfrac{1}{{T}_{2}}\right]

ln⁡(5)=Ea8.314[1300−1315]\ln ( 5 ) = \dfrac{Ea}{8 . 314}\left[\dfrac{1}{300} - \dfrac{1}{315}\right]

1.6094=Ea8.314[15300×315]1 . 6094 = \dfrac{Ea}{8 . 314}\left[\dfrac{15}{300 \times 315}\right]

Ea=84297JEa = 84297J

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