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JEE Main20198 Apr 2019Evening ShiftChemistryChemical KineticsActual

For a reaction scheme A → k 1 B → k 2 C , if the net rate of formation of B is set to be zero then the concentration of B is given by:

Options

  1. Ak 1 + k 2 [ A ]
  2. Bk 1 k 2 [ A ]
  3. Ck 1 k 2 [ A ]
  4. Dk 1 - k 2 [ A ]

Correct answer

C. k 1 k 2 [ A ]

Step-by-step solution

d B d t = Rate of formation of B - Rate of dissociation of B d B d t = k 1 A - k 2 B Given;     d B d t = 0   k 1 A - k 2 B = 0 B = k 1 A k 2

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