JEE Main 20198 AprilEvening Shift
- Exam
- JEE Main
- Year
- 2019
- Date
- 8 April
- Shift
- Evening Shift
- Subject
- Chemistry
- Chapter
- Chemical Kinetics
JEE Main 2019 · 8 April · Evening Shift · Chemistry · Chemical Kinetics
For a reaction scheme A k _ 1 → B k _ 2 → C, if the net rate of...
For a reaction scheme if the net rate of formation of B is set to be zero then the concentration of B is given by:
Options
- A
- B
- C
- D
Correct answer
C.
Step-by-step solution
\dfrac{d\left[B\right]}{dt} =B -B\dfrac{d\left[B\right]}{dt} = {k}_{1}\left[A\right] - {k}_{2}\left[B\right]\dfrac{d\left[B\right]}{dt} = 0{k}_{1}\left[A\right] - {k}_{2}\left[B\right] = 0