JEE Main 20198 AprilMorning Shift
- Exam
- JEE Main
- Year
- 2019
- Date
- 8 April
- Shift
- Morning Shift
- Subject
- Chemistry
- Chapter
- Chemical Kinetics
JEE Main 2019 · 8 April · Morning Shift · Chemistry · Chemical Kinetics
For the reaction 2A + B → C , the values of initial rate at...
For the reaction , the values of initial rate at different reactant concentrations are given in the table below. The rate law for the reactions is:
| 0.05 | 0.05 | 0.045 |
| 0.10 | 0.05 | 0.090 |
| 0.20 | 0.10 | 0.72 |
Options
- ARate = k{[ A ]}^{2} [ B ]
- BRate = k{[ A ]}^{2}{[ B ]}^{2}
- CRate = k [ A ] [ B ]
- DRate = k [ A ] {[ B ]}^{2}
Correct answer
D. Rate = k [ A ] {[ B ]}^{2}
Step-by-step solution
From the experiment (1) and (2)
From the experiment (2) and (3)
\left(\dfrac{1}{2}\right){\left(\dfrac{1}{2}\right)}^{y} = \dfrac{0.09}{0.72}{\left(\dfrac{1}{2}\right)}^{y} = \dfrac{0.09 \times 2}{0.72}{\left(\dfrac{1}{2}\right)}^{y} = \left(\dfrac{1}{4}\right)y = 22 and B = 2∴ R ∝ \left[A\right]{\left[B\right]}^{2}R = K\left[A\right]{\left[B\right]}^{2}