JEE Main20198 Apr 2019Morning ShiftChemistryChemical KineticsActual
For the reaction 2 A + B → C , the values of initial rate at different reactant concentrations are given in the table below. The rate law for the reactions is: [ A ] ( m o l   L - 1 ) [ B ] ( m o l   L - 1 ) I n i t i a l R a t e ( m o l   L - 1 s - 1 ) 0.05 0.05 0.045 0.10 0.05 0.090 0.20 0.10 0.72
Options
- AR a t e = k [ A ] 2 [ B ]
- BR a t e = k [ A ] 2 [ B ] 2
- CR a t e = k [ A ] [ B ]
- DR a t e = k [ A ] [ B ] 2
Correct answer
D. R a t e = k [ A ] [ B ] 2
Step-by-step solution
From the experiment (1) and (2) 0.05 0.10 x 0.05 0.05 y = 0.045 0.090 1 2 x = 1 2 ⇒ x = 1 From the experiment (2) and (3) 0.1 0.2 x 0.05 0.1 y = 0.09 0.72 1 2 1 2 y = 0.09 0.72 1 2 y = 0.09 × 2 0.72 1 2 y = 1 4 y = 2 Order of reaction with respect to A is 2 and B = 2 ∴ R ∝ A B 2 Or R = K A B 2