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JEE Main201912 Jan 2019Evening ShiftChemistryChemical KineticsActual

For a reaction, consider the plot of l n   k versus 1 / T given in the figure. If the rate constant of this reaction at 400   K is 10 - 5 s - 1 , then the rate constant at 500   K is:

Options

  1. A10 - 4 s - 1
  2. B10 - 6 s - 1
  3. C2 x 10 - 4 s - 1
  4. D4 x 10 - 4 s - 1

Correct answer

A. 10 - 4 s - 1

Step-by-step solution

l n   k = l n   A - E a R T = l n   A - 4606 1 T 1 - 1 T 2 ∴ E A R = 4606 l n   k 10 - 5 = 4606 × 500 - 400 500 × 400 l n   k 10 - 5 = 4606 × 1 2000 = 2.303 l n   k 10 - 5 = l n   10 k = 10 - 4 s - 1

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