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JEE Main201815 Apr 2018Evening ShiftChemistryChemical KineticsActual

For a first order reaction, A P , t _ 1 / 2 (half-life) is 10 days. The time required for 1 4 ^ th conversion of A (in days) is: ( 2=0.693, 3=1.1) .

Options

  1. A3.2
  2. B2.5
  3. C4.1
  4. D5

Correct answer

C. 4.1

Step-by-step solution

The half life t _ 1 / 2 =10 days The decay constant k = 0.693 t _ 1 / 2 = 0.693 10 days =0.0693 days ⁻¹ The time required for one fourth conversion aligned & t = 2.303 k ₁₀ a a - x &= 2.303 0.0693 day ⁻¹ ₁₀ 1 1-(1 / 4) =4.1 days aligned

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