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JEE Main 202622 JanuaryEvening Shift
Exam
JEE Main
Year
2026
Date
22 January
Shift
Evening Shift
Subject
Chemistry
Chapter
Classification of Elements and Periodicity in Properties

JEE Main 2026 · 22 January · Evening Shift · Chemistry · Classification of Elements and Periodicity in Properties

Given below are two statements : Statement I : C Statement II :...

Given below are two statements :
Statement I: C<O<N<F\quad \mathrm{C}<\mathrm{O}<\mathrm{N}<\mathrm{F} is the correct order in terms of first ionization enthalpy values.
Statement II: S>Se>Te>Po>O\quad \mathrm{S}>\mathrm{Se}>\mathrm{Te}>\mathrm{Po}>\mathrm{O} is the correct order in terms of the magnitude of electron gain enthalpy values.
In the light of the above statements, choose the correct answer from the options given below :

Options

  1. AStatement I is true but Statement II is false
  2. BStatement I is false but Statement II is true
  3. CBoth Statement I and Statement II are false
  4. DBoth Statement I and Statement II are true

Correct answer

D. Both Statement I and Statement II are true

Step-by-step solution

Statement I:
Ionization enthalpy generally increases across a period from left to right.
However, Nitrogen (2s22p32s^2 2p^3) has a stable half-filled electronic configuration, making it harder to remove an electron compared to Oxygen (2s22p42s^2 2p^4).
Thus, the order is C<O<N<FC < O < N < F.
Statement I is true.

Statement II:
For Group 16 elements, Oxygen has an exceptionally low magnitude of electron gain enthalpy due to its small size and high inter-electronic repulsions in the 2p2p subshell.
The magnitude of electron gain enthalpy decreases down the group from Sulphur onwards.
The correct order of magnitude is S>Se>Te>Po>OS > Se > Te > Po > O.
Statement II is true.

Both statements are correct.
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