The successive 5 ionisation energies of an element are 800,2427,3658,25024 and 32824 ~kJ / mol , respectively. By using the above values predict the group in which the above element is present :

Step-by-step solution

The successive 5 ionisation energies of an element are 800,2427,3658,25024 and 32824 ~kJ / mol , respectively. aligned & IE ₂ IE ₁ = 2427 800 =3.03 & IE IE ₂ = 3658 2427 =1.51 & IE IE ₃ = 25024 3658 =6.84 aligned IE ₅ IE ₄ = 32824 25024 =1.31 Since ( IE ₄ / IE ₃ ) value is maximum, the element belongs to group 13.