JEE Main20241 Feb 2024Morning ShiftChemistryClassification of Elements and Periodicity in PropertiesActual
In case of isoelectronic species the size of F – , Ne and Na + is affected by:
Options
- APrincipal quantum number n
- BNone of the factors because their size is the same
- CElectron-electron interaction in the outer orbitals
- DNuclear charge z
Correct answer
D. Nuclear charge z
Step-by-step solution
In F - , Ne , Na + all have 1 s 2 , 2 s 2 , 2 p 6 configuration. They have different size due to the difference in nuclear charge. For isoelectronic species, the more nuclear charges, the less will be the size of the species. The valence electrons will experience a greater attractive force due to the increase in nuclear charge. Hence, the size of isoelectronic species - F - , Ne and Na + is affected by nuclear charge Z . Thus, the ionic size of Na + is the lowest, and the ionic size of F - ion is the highest. Hence