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JEE Main 202431 JanuaryEvening Shift
Exam
JEE Main
Year
2024
Date
31 January
Shift
Evening Shift
Subject
Chemistry
Chapter
Classification of Elements and Periodicity in Properties

JEE Main 2024 · 31 January · Evening Shift · Chemistry · Classification of Elements and Periodicity in Properties

Consider the following elements. Which of the following is/are true...

Consider the following elements.

Consider the following elements. Which of the following is/are true about A ^ ' , B ^ ' , C ^ ' and D ^ ' ? A. Order of

Which of the following is/are true about A′,B′,C′{A}^{'}, {B}^{'}, {C}^{'} and D′{D}^{'} ?

A. Order of atomic radii: B′<A′<D′<C′{B}^{'} < {A}^{'} < {D}^{'} < {C}^{'}

B. Order of metallic character : B′<A′<D′<C′{B}^{'} < {A}^{'} < {D}^{'} < {C}^{'}

C. Size of the element : D′<C′<B′<A′{D}^{'} < {C}^{'} < {B}^{'} < {A}^{'}

D. Order of ionic radii : B′+<A′+<D′+<C′+{{B}^{'}}^{+} < {{A}^{'}}^{+} < {{D}^{'}}^{+} < {{C}^{'}}^{+}

Choose the correct answer from the options given below:

Options

  1. AA only
  2. BA, B and D only
  3. CA and B only
  4. DB, C and D only

Correct answer

B. A, B and D only

Step-by-step solution

In a group the atomic size increases due to the addition of shells as we move from one period to another. Across a period the atomic size decreases as the number of shells remain the same while the nuclear charge increases. This leads to the pulling of electrons from the outermost shell towards the nucleus thereby decreasing the size.

 Metallic character increases as we move down the group because the atomic size increases which lead to easy loss of electrons. On the other hand, it decreases across a period as we move from left to right. This happens because there is an increase in nuclear charge which makes it difficult for an atom to lose electrons.

In general along the period from left to right, size decreases and metallic character decreases.

In general down the group, size increases and metallic character increases.

B′<A′{B}^{'} < {A}^{'} (size) C′>A′{C}^{'} > {A}^{'} (size)

D′<C′{D}^{'} < {C}^{'} (size) D′>B′{D}^{'} > {B}^{'} (size)

B′<A′{B}^{'} < {A}^{'} (metallic character)

D′<C′{D}^{'} < {C}^{'} (metallic character)

B′+<A′+{{B}^{'}}^{+} < {{A}^{'}}^{+} (size)

D′+<C′+{{D}^{'}}^{+} < {{C}^{'}}^{+} (size)

∴∴ C statement is incorrect.

Hence ,option B is the answer.

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