JEE Main202116 Mar 2021Evening ShiftChemistryClassification of Elements and Periodicity in PropertiesActual
Identify the elements X and Y using the ionization energy values given below : Ionization energy ( kJ / mol ) 1 st 2 nd X 495 4563 Y 731 1450
Options
- AX = Na ; Y = Mg
- BX = Mg ; Y = F
- CX = Mg ; Y = Na
- DX = F ; Y = Mg
Correct answer
A. X = Na ; Y = Mg
Step-by-step solution
Na → Ne 3 s 1 IE 1 is very low but IE 2 is very high due to stable noble gas configuration of Na + . Mg → Ne 3 s 2 IE 1 and IE 2 → Low IE 3 is very high.