JEE Main 201912 JanuaryMorning Shift

Exam: JEE Main
Year: 2019
Date: 12 January
Shift: Morning Shift
Subject: Chemistry
Chapter: Classification of Elements and Periodicity in Properties

JEE Main 2019 · 12 January · Morning Shift · Chemistry · Classification of Elements and Periodicity in Properties

The element with Z = 120 (not yet discovered) will be a/an

The element with

Z = 120

(not yet discovered) will be a/an

Options

Atransition metal.
Balkaline earth metal.
Calkali metal.
Dinner-transition metal.

Correct answer

B. alkaline earth metal.

Step-by-step solution

$\left[{Og}_{118}\right]8{s}^{2}$ is the configuration for $Z = 120$ .

Since the differentiating electron is entering in the $s -$ orbital, the element will belong to the s-block and the outermost s-orbital is having two electrons. Hence, It will belong to the alkaline earth metal group.

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