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JEE Main2015ChemistryClassification of Elements and Periodicity in PropertiesActual

The ionic radii ( in Å ) of N 3 - , O 2 - and F - are respectively:

Options

  1. A1 . 71 ,   1 . 36   and   1 . 40
  2. B1 . 36 ,   1 . 40   and   1 . 71
  3. C1 . 36 ,   1 . 71   and   1 . 40
  4. D1 . 71 ,   1 . 40   and   1 . 36

Correct answer

D. 1 . 71 ,   1 . 40   and   1 . 36

Step-by-step solution

As Z e ↑ ionic radius decreases for isoelectronic species. Z = number   of   protons e = number   of   electrons N 3 - Z e = 7 1 0 O 2 - Z e = 8 1 0 F - Z e = 9 1 0 Trend of ionic radius: N 3 - > O 2 - > F -

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